Steel Buildings in Europe

Title 3.4 Worked Example – Fin Plate 4 of 13 5 – 41 V Ed = 350 kN ≤ 584 kN, OK 3.2.1.2. Bearing resistance of bolts on the fin plate Basic requirement: V Ed ≤ V Rd V Rd = 2 hor,Rd b, b 2 b,ver,Rd b b 1               F n F n n   Ref [3] α = 0,022 and β = 0,105, as above The vertical bearing resistance of a single bolt, F b,ver,Rd = M2 u,p p 1 b   dt f k Table 3.4 k 1 =         min 2,8 1,7; 1,4 1,7; 2,5 0 2 0 2 d p d e =         1,7; 2,5 22 1,7; 1,4 60 22 min 2,8 50 = min( 4,67; 2,12; 2,5) = 2,12 α b =          ; 1,0 ; 4 1 3 ; 3 min u,p ub 0 1 0 1 f f d p d e =          ; 1,0 430 ; 800 4 1 3 22 ; 70 3 22 40 min = min( 0,61; 0,81; 1,86; 1,0) = 0,61 F b,ver,Rd = 3 10 1,25 2,12 0,61 430 20 10       = 89 kN The horizontal bearing resistance of a single bolt, F b,hor,Rd = M2 u,p p 1 b   dt f k Table 3.4 k 1 =         min 2,8 1,7; 1,4 1,7; 2,5 0 1 0 1 d p d e =         1,7; 2,5 22 1,7; 1,4 70 22 min 2,8 40 = min( 3,39; 2,75; 2,5) = 2,5 α b =          ; 1,0 0,25; 3 ; 3 min u,p ub 0 2 0 2 f f d p d e =          ; 1,0 430 0,25; 800 3 22 ; 60 3 22 min 50 = min( 0,75; 0,66; 1,0) = 0,66 F b,hor,Rd = 3 10 1,25 2,5 0,66 430 20 10       = 114 kN V Rd = 2 2 114 0,105 10 89 1 0, 022 10 10                 = 605 kN